The tangential haste(velocity) of the block m1 on the amicable(frictionless) table is1.34 m/s.
The given parameters;
mass of the first block, m1 = 2 kg
mass of the alternate block, m2 = 5 kg
distance of block m1, R = 0.75 m
The net torque on both blocks is calculated as
T( net) = Iα
T2R2- T1R1 = Iα
where;
T ₁ is the (tension)pressure on first block
I is the moment of inertia of point mass
α is the angular acceleration
T1 = m1g m1a
T2 = m2g m2a
The acceleration of both blocks is calculated as follows
R( T2- T1) = MR ² x( a/ R)
R( T2- T1) = MRa
(T2- T1) = M*a
g( m2- m1) = a( M m1 m2)
Where,
M is the mass of string = 0
g( m2- m1) = a( m1 m2)
a = 1.88 m/ s ²
The speed of the block m1 is calculated as follows;
a = v ²/ r
v = ar
v = 1.88 *0.75
v = 1.34 m/ s
Therefore, the tangential velocity of the block m1 on the frictionless table is 1.34 m/s.
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