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Sagot :
There would be a 68% chance that the average blood pressure would be between 193 to 197.
The subset chosen from the larger set to make assumptions is known as a random sample. A range of values is a confidence interval.
We know that,
E = z ( α / 2 ) × σ / √n → 1
As per the given question,
- Blood pressure in a population of very at risk people has an expected value ( x ) = 195
- Standard deviation ( σ ) = 20
- Number of random samples ( n ) = 100
For 68% confidence,
z ( α / 2 ) = 0.9944
Substitute the values in 1,
E = z ( α / 2 ) × σ / √n
= 0.9944 × 20 / √100
= 0.9944 × 20 / 10
= 0.9944 × 2
E = 1.9888 ≅ 1.99
Let us consider,
⇒ x - E < μ < x + E
⇒ 195 - 1.99 < μ < 195 + 1.99
⇒ 193.01 < μ < 196.99
⇒ 193 < μ < 197 ( ∵ 193.01 ≅ 193 and 196.99 ≅ 197 )
⇒ μ = ( 193 , 197 )
Therefore, A 68% chance that the average blood pressure lies between 193 to 197. Hence Option b is correct.
To know more about confidence interval problems refer to:
https://brainly.com/question/10126826
#SPJ4
The complete question is
Blood pressure in a population of very at risk people has an expected value of 195 and a standard deviation of 20. Suppose you take a random sample of 100 of these people. There would be a 68% chance that the average blood pressure would be between Select one:
a.) 155 to 235
b.) 193 to 197
c.) 175 to 215
d.) 191 to 199
e.) 200 to 230
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