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in a double slit experiment light of wavelength 585.0 nm is used, the separation of the slits is 0.100 mm and the viewing screen is 21.0 cm from the slits. on this screen, what is the separation between the fifth maximum and seventh minimum from the central maximum?

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The separation between fifth maximum and seventh minimum from central maximum is calculated to be 2.457mm.

What is the double-slit experiment?

The double-slit experiment shows that light and matter can exhibit the properties of classically defined waves and particles. This experiment was first performed by Thomas Young in 1802 to demonstrate the wave behavior of visible light

This experiment belongs to general class of double-path experiments, in which a wave is split into two separate waves. Changes in the path length of both the waves leads to a phase shift that creates interference patterns.

Separation between 5th and 7th minima is,

= 2 * (wavelength)x(Distance of the screen) / (slit separation)

=(2x 585x10^-9 x21x10^-2 )/ 0.1x10^-3

Hence, Separation between 5th and 7th minima is =2.457mm.

To know more about double slit experiment, refer

https://brainly.com/question/29381229

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