Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
The reactivity series according to SN1 reactions is as follows: 2-iodo-2-methylpentane > 2-bromo-2-methylpentane > 2-chloro-2-methylpentane > 2-chloro-2-methylpentane.
In this above case, the Sn1 reaction would form a carbocation. So, the molecule will be more reactive if will generate a very stable carbocation. We have to remember that the tertiary carbocations are the more stable ones. Keeping this in mind, 3-chloropentane would be the least reactive molecules of all.
Then to identify which one is more reactive among the other ones, we must check the leaving group. In this given case, all the atoms are halogens, so if we have a larger atom then the leaving group would leave more easily.
Keeping this his in mind the larger atom would be I, then Br and finally Cl, therefore, the 2-iodo-2-methylpentane would be the more reactive one.
The given question is incomplete and the complete question is given as,
Rank the following alkyl halides from most reactive to least reactive in an SN1 reaction: 2-bromo-2-methylpentane, 2-chloro-2-methylpentane, 3-chloropentane, and 2-iodo-2-methylpentane. Rank the alkyl halides from most reactive to least reactive. To rank items as equivalent, overlap them. ResetHelp Least reactiveMost reactive
Learn more about SN1 reactions from the link given below.
https://brainly.com/question/12242526
#SPJ4
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
