Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
The test statistic value is -1.0328.
The null hypothesis state that the no-show rate for passengers booked on a flight is 6% and the alternative hypothesis state that the no-show rate is less than 6%. The sample proportion, in this case, can be calculated as,
ˆp = [tex]\frac{18}{360} = 0.0474[/tex]
The z-test statistic value can be calculated as,
[tex]z= \frac{^p-P}{\sqrt{\frac{P*(1-P)}{n} } }[/tex]
[tex]or, \frac{0.0474-0.06}{\sqrt{\frac{0.06*0.94}{380} } }[/tex]
[tex]or, \frac{-0.0126}{0.0122}\\ or, -1.0328[/tex]
The test statistic value is -1.0328.
Now the p-value can be calculated using the excel function =[tex]NORM.S.DIST(-1.0328,TRUE)[/tex] as 0.1508. The p-value is greater than 0.10 so we can conclude to not reject the null hypothesis at a 10% level of significance. Therefore, we do not have enough evidence to state that the no-show rate is less than 6%.
To learn more about hypothesis testing visit: brainly.com/question/17099835
#SPJ4
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
