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there are 44 sets of balls numbered 11 through 1010 placed in a bowl. if 44 balls are randomly chosen without replacement, find the probability that the balls have the same number. express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

Sagot :

The probability that the balls have the same number is 0.001094 = 0.1094%.

The probability can be calculated using the hypergeometric distribution, a discrete probability distribution that calculates the likelihood an event occurs k times in n trials when you are sampling from a small population without replacement.

Hypergeometric distribution is used because the balls are chosen without replacement.

Hypergeometric distribution formula:

P (X = x) = h (x, N, n, k) = [tex]\frac{Ck,xCN-k,n-x}{CN,n}[/tex]

with parameters as follows:

x = the number of successes.

N = the size of the population.

n = the size of the sample.

k = the total number of desired outcomes.

In this case, we have given data:

There are 40 balls, so N = 40.

For each number, there are 4 balls, so k = 4.

4 balls are selected, hence n = 4.

For each ball, the probability is P (X = 4). There are 10 balls, so we have to find 10P (X = 4).

P (X = x) = h (x, N, n, k) = [tex]\frac{Ck,xCN-k,n-x}{CN,n}[/tex]

P (X = 4) = h (4, 40, 4, 4) = [tex]\frac{C4,4C26,0}{C40,4}[/tex] = 0.0001094

0.0001094 x 10 = 0.001094

Hence, 0.001094 = 0.1094% is the probability that the balls have the same number.

Learn more about probability at: https://brainly.com/question/11234923

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