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Sagot :
The temperature of the diver's is 1403K when it reaches the surface if the process involved is adiabatic.
Firstly we need to find the radius of air bubble, as we apply the ideal gas equation.
Since, we know that an air bubble is spherical in size, so volume of sphere is =(4/3)πr³ where r is the radius of the air bubble.
Volume of air bubble=(4/3)πr³
=>V=(4/3)×π×(0.065)³
=>V=(4/3)×3.14×0.274625
=>V=3.44929/3
=>V=1.149m³
Since temperature given in degree, so in kelvin temperature is =C+273=37+273=310K
Now, we apply the ideal gas equation which is
=>PV=nRT
So,we firstly find value of nR,=>nR=(PV)/T
=>nR= (1.15×1.149)/ 310
=>nR=0.0042
Since, it is given that the process is adiabatic, so we can use formula of work
For air,we know that value of γ is 1.4
=>W=(nR/γ-1) ×(T₁ - T₂)
=>W=[0.0042/ 1.4-1]×(T-310)
=>W=(0.0042/0.4) ×(T-310)
=>W=0.010×(T-310)
=>10.93=0.010×(T-310)
=>10.93/0.010=T-310
=>1093=T-310
=>T=1093+310
=>T=1403K
Hence, required temperature is 1403K.
To know more about Temperature, visit here:
https://brainly.com/question/11464844
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