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consider the interference resulting from sending coherent visible light perpendicularly through this pair of openings. calculate the angle between adjacent zones of constructive interference, assuming the width of your middle finger to be 2.5 cm and the wavelength of the light to be 690 nm.

Sagot :

The angle as the constructive interference is 1.485×[tex]10^{-3}[/tex]

Calculate the angle as follows:

For constructive interference,

∅ = [tex]sin^{-1} \frac{n}{d}[/tex]λ

   = [tex]sin^{-1} \frac{1*700*10^{-9}m}{0.027m}[/tex] = [tex]1.485* 10^{-3}degrees.[/tex]

In physics, the wavelength is the spatial length of a periodic wave—the distance over which the wave's form repeats. it is the space between consecutive corresponding factors of the same section on the wave, consisting of adjoining crests, troughs, or 0 crossings, and is a characteristic of both visiting waves and standing waves, in addition to other spatial wave patterns. The inverse of the wavelength is known as the spatial frequency. Wavelength is generally particular via the Greek letter lambda (λ). The time period wavelength is likewise once in a while applied to modulated waves, and to the sinusoidal envelopes of modulated waves or waves shaped by means of interference of several sinusoids.

Assuming a sinusoidal wave transferring at a hard and fast wave velocity, the wavelength is inversely proportional to the frequency of the wave: waves with better frequencies have shorter wavelengths, and lower frequencies have longer wavelengths.

To learn more about Wavelength visit here:

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Complete Question:

Consider the interference resulting from sending coherent visible light perpendicularly through this pair of openings. Calculate the angle between adjacent zones of constructive interference, assuming the width of your middle finger to be 2.7 cm and the wavelength of the light to be 700 nm.

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