The speed of the water coming out of the nozzle of the hose is 1.92m/s.
The speed V of any object at the bottom when it is thrown with speed U from the height H is given by the formula,
MgH + 1/2MU² = 1/2MV²
gH + U²/2 = V²/2
Where,
g is the gravitational acceleration,
H is the height from which the object is thrown.
Now it is given to us that horse lying on the ground has water coming out of it at a speed of 5.4m/s. Now the nozzle of the hose is lifted to a height of 1.3 m a ground.
So, we can find the speed of the water coming out of the hose,
Putting values,
9.8(1.3) + (5.4)²/2 = V²/2
Solving further,
V = 1.92m/s.
So, the speed of the water coming out of the hose is 1.92m/s.
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