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an object is thrown upward with a speed of 12 m/s on the surface of planet x where the acceleration due to gravity is 1.5 m/s2. what is the maximum height reached by the object?

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The maximum height reached by the object thrown with a speed of 12 m/s is 48 m

The initial velocity = 12 m/s

The acceleration due to gravity = -1.5 m/s²

The final velocity of the object = 0

The maximum height reached can be found using the formula,

              x = ut + 1/2at²

where x is the height

          u is the initial speed

          t is the time taken

         a is the acceleration due to gravity

So, the time can be found using the formula,

           v = u + at

where v is the final speed

           u is the initial speed

Let us substitute the known values in the above equation, we get

         0 = 12 - 1.5t

        1.5t = 12

            t = 12/1.5

              = 8s

Now, the maximum height is

          x = 12(8) +1/2(-1.5)(8)²

             = 96 - 48

             = 48 m

Therefore, the maximum height reached is 48m

Learn more about the speed in

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