Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

an object is thrown upward with a speed of 12 m/s on the surface of planet x where the acceleration due to gravity is 1.5 m/s2. what is the maximum height reached by the object?

Sagot :

Qwdog

The maximum height reached by the object thrown with a speed of 12 m/s is 48 m

The initial velocity = 12 m/s

The acceleration due to gravity = -1.5 m/s²

The final velocity of the object = 0

The maximum height reached can be found using the formula,

              x = ut + 1/2at²

where x is the height

          u is the initial speed

          t is the time taken

         a is the acceleration due to gravity

So, the time can be found using the formula,

           v = u + at

where v is the final speed

           u is the initial speed

Let us substitute the known values in the above equation, we get

         0 = 12 - 1.5t

        1.5t = 12

            t = 12/1.5

              = 8s

Now, the maximum height is

          x = 12(8) +1/2(-1.5)(8)²

             = 96 - 48

             = 48 m

Therefore, the maximum height reached is 48m

Learn more about the speed in

https://brainly.com/question/16888861

#SPJ4

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.