If top number as X and the bottom number as Y, so the quotient would be X / Y = 9 with a remainder 5 general problem look like X = 9Y + 5, where Y> 5 .
In division, we look at the relationship between dividend, divisor, quotient, and remainder. The divided number is called the dividend. The number you divide by is called the divisor. The result obtained is called the quotient. The remaining number is called the remainder.
Dividend = Divisor × Quotient + Remainder
We know that the quotient is 9 and the remainder is 5. We need to find two dividends that satisfy these conditions. The equation becomes: Dividend
= Divisor × 9 + 5
The remainder must be less than the divisor. We must choose a divisor greater than 5. The table below shows the first few that meet these conditions.
Divisor Dividend Result
6 6×9+5 = 59 9 Remainder 5
7 7×9 + 5 = 68 9 Remainder 5
8. 8×9 + 5 = 77 9 Remainder 5
9 9×9 + 5 = 86 9 remainder 5
10 10×9 + 5 = 95. 9 remainder 5
11 11×9 + 5 = 104. 9 remainder 5
...
Using this formula, we can continue this table to generate any number of dividends with a quotient of 9 and a remainder of 5. Note that each 9 is more than the previous one.
To learn more about Remainder and quotient, refer:
https://brainly.com/question/28799524
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