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write the balanced chemical equation between h2so4 and koh in aqueous solution. this is called a neutralization reaction and will produce water and potassium sulfate.

Sagot :

The balanced chemical equation between h2so4 and koh in aqueous solution ; H2SO4 (aq) + 2KOH (aq) --------> K2SO4 (aq)+ 2H2O (l)

Next, calculate moles of each reactant:

0.650 L X 0.430 M H2SO4 = 0.2795 mol H2SO4

0.600 L X 0.240 M KOH = 0.144 mol KOH

Next, calculate moles of H2SO4 consumed by the KOH:

1 eq of H2SO4  reacts with 2 eq of KOH

0.144 / 2 M KOH = 0.072 M of H2SO4 would be reacted

So, remaining moles of H2SO4 = 0.2795 - 0.072 = 0.2075 mol H2SO4

This is in a total volume of 1.25 L, so the concentration of H2SO4 is:

0.2075 mol / 1.25 L = 0.166 M

As a base, KOH is very reactive, while H2SO4 is a highly reactive acid. If a dilute solution of each acid and base is combined, a neutralization reaction will occur.

In this example, the neutralization process would produce water as a byproduct and K2SO4 as the salt as its end products.

Learn more about to chemical equation visit here;

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