At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
25 babies would expect to have cystic fibrosis, a homozygous recessive condition.
As per the data given in the above question,
The data given in the question are as follow,
Total number of individuals is 2500.
Ans the frequency of the dominant allele is 0.9.
Also the population is at hardy-weinberg equilibrium.
Then how many babies would you expect to have cystic fibrosis?
So the frequency of dominate allele (p) + frequency of recessive (CF) allele (q)=1
[tex]0.9+q=1\\q=1-0.9[/tex]
Further solving we get,
q=0.1
Frequency of CF genotype [tex]=q^2=(0.1)^2=0.01 \:or1\%[/tex]
Therefore the expected no of babies with CF,
[tex]=0.01\times 2500\\=25[/tex]
A homozygous recessive disease called cystic fibrosis would be anticipated in 25 newborns.
For more such question on cystic fibrosis
https://brainly.com/question/2290129
#SPJ4
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.
