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Sagot :
The required confidence interval for the corresponding population team is 4564.94 ≤ μ ≤ 4635.06.
Given:
Mean (μ) = $4600
Standard deviation (σ) = $800
Sample size (n) = 2000
Confidence interval = 95%
we have to find the 95% confidence interval for the given population mean. The formula used to find the interval of mean is:
μ ± z [tex]\frac{S.D}{\sqrt{n}}[/tex]
The z value for 95% confidence interval is 1.96.
So, the interval of mean at given confidence level will be,
= [tex]4600[/tex] ± [tex]1.96(\frac{800}{\sqrt{2000} } )[/tex]
= 4564.94 ≤ μ ≤ 4635.06
Therefore, the required confidence interval for the corresponding population mean is 4564.94 ≤ μ ≤ 4635.06.
To know more about confidence interval here. https://brainly.com/question/13799736#
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