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Sagot :
a)equation : y - 5 = 2/3(x + 6)
b)slope of the equation is m = -3
the above line contains the point ([tex]x_{1}[/tex],[tex]y_{1}[/tex]) = (5,-1)
c)slope of the above equation m = -3
d) (y - 3) = 2(x-4)
e)slope of the equation m = -1/2
y-intercept = 0
f)equation: y + 2 = 7(x+4)
given that
a)slope is 2/3 and goes through point (-6,5)
the equation for the above given values are
y - [tex]y_{1}[/tex] = m(x - [tex]x_{1}[/tex])
([tex]x_{1}[/tex],[tex]y_{1}[/tex]) = (-6,5)
m = 2/3
equation : y - 5 = 2/3(x + 6)
b)the given equation y + 1 = -3(x-5)
slope of the equation is m = -3
the above line contains the point ([tex]x_{1}[/tex],[tex]y_{1}[/tex]) = (5,-1)
c) for the equation y + 1 = -3(x - 5),the line contains the point (5, -1) and has a slope of?
slope of the above equation m = -3
d)rewrite y 3 2 x 4 in slope intercept form
(y - 3) = 2(x-4)
e) given the equation, 3x - 2y = -10, identify the slope and the y-intercept.
slope of the equation m = -1/2
y-intercept = 0
f) write an equation in slope-intercept form from the points (-4, -2) and (-3, 5)
[tex]\frac{y - y_{1} }{y_{2} - y_{1} }[/tex] = [tex]\frac{x - x_{1} }{x_{2} - x_{1} }[/tex]
[tex]\frac{y + 2}{5 + 2}[/tex] = [tex]\frac{x + 4}{-3 + 4}[/tex]
[tex]\frac{y + 2}{7}[/tex] = [tex]\frac{x + 4}{1}[/tex]
y + 2 = 7(x+4)
To learn more about slope-intercept :
https://brainly.com/question/19824331
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