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a hockey puck is given an initial speed of 5.1 m/s . part a if the coefficient of kinetic friction between the puck and the ice is 0.05, how far does the puck slide before coming to rest? solve this problem using conservation of energy.

Sagot :

Disatance the puck slide before coming to rest

d=26.54m

Conservation of energy?

According to the law of the conservation of energy :

[tex]E_{i}-E_{f} =W_{f}[/tex]

where [tex]E_{i}[/tex] is the initial energy,[tex]E_{f}[/tex]  is the final energy and  [tex]W_{f[/tex] is the work of the friction.

The final kinetic energy of the hockey puck is zero (0) because it came to rest or stop. So our equation becomes

[tex]E_{i}=W_{f}[/tex]

Here,

[tex]E_{i}=\frac{1}{2} M V^{2}[/tex]

where M is the mass and V the velocity.

[tex]W_{f}=U_{k}Nd[/tex]

where [tex]U_{k}[/tex]  is the coefficient of kinetic friction, N is the normal force and d is the distance.

So

[tex]\frac{1}{2} M V^{2}=U_{k}Nd[/tex]

[tex]\frac{1}{2} M V^{2}=U_{k}M g d[/tex]

[tex]\frac{1}{2} V^{2}=U_{k} g d[/tex]

[tex]\frac{1}{2} (5.1 ^{2})=9.8 (0.05)d[/tex]

[tex]d=\frac{\frac{1}{2} (5.1 ^{2})}{9.8 (0.05)}[/tex]

[tex]d=26.54[/tex] m

To learn more about Conservation of energy here: https://brainly.com/question/14020055

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