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Sagot :
Disatance the puck slide before coming to rest
d=26.54m
Conservation of energy?
According to the law of the conservation of energy :
[tex]E_{i}-E_{f} =W_{f}[/tex]
where [tex]E_{i}[/tex] is the initial energy,[tex]E_{f}[/tex] is the final energy and [tex]W_{f[/tex] is the work of the friction.
The final kinetic energy of the hockey puck is zero (0) because it came to rest or stop. So our equation becomes
[tex]E_{i}=W_{f}[/tex]
Here,
[tex]E_{i}=\frac{1}{2} M V^{2}[/tex]
where M is the mass and V the velocity.
[tex]W_{f}=U_{k}Nd[/tex]
where [tex]U_{k}[/tex] is the coefficient of kinetic friction, N is the normal force and d is the distance.
So
[tex]\frac{1}{2} M V^{2}=U_{k}Nd[/tex]
[tex]\frac{1}{2} M V^{2}=U_{k}M g d[/tex]
[tex]\frac{1}{2} V^{2}=U_{k} g d[/tex]
[tex]\frac{1}{2} (5.1 ^{2})=9.8 (0.05)d[/tex]
[tex]d=\frac{\frac{1}{2} (5.1 ^{2})}{9.8 (0.05)}[/tex]
[tex]d=26.54[/tex] m
To learn more about Conservation of energy here: https://brainly.com/question/14020055
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