Answered

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Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; all otherscompleted the test. FR(%) is __________ and MTBF is __________.
A) 10%; 1/1820
B) 90%; 1/1820
C) 10%; 1820 hours
D) 10%; 1980 hours
E) cannot calculate from information provided

Sagot :

namrata421

20% failure rate MTBF equals 880 hrs as evidence 10 batteries a 200-hour test A failure equals 20 hours a second failure after 140 hours

solution

We are aware that the formula for the mean time between failures is: = (total uptime) / (number of breakdowns)...................1.

hence, the Total Uptime here will be

Uptime total = 200 x 10

2000 hours total uptime

and this

1 at 20 hours and another at 140 hours equals the number of breakdowns.

Therefore, the equation will be: = (Total up time) (Number of breakdowns)...2

= = 1000

there is a gap between these instances.

occurrences separated by 140 - 20

gap = 120 hours between occurrences

and

MTBF is going to

MTBF = 1000 - 120

MTBF equals 880 hrs.

and

There will be a failure rate (FR).

Failure rate (FR) = 1 Mean Time Between Failures................3

Reject rate=20%

To know more about failure rate visit:-

https://brainly.com/question/13652179

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