Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; all otherscompleted the test. FR(%) is __________ and MTBF is __________.
A) 10%; 1/1820
B) 90%; 1/1820
C) 10%; 1820 hours
D) 10%; 1980 hours
E) cannot calculate from information provided

Sagot :

namrata421

20% failure rate MTBF equals 880 hrs as evidence 10 batteries a 200-hour test A failure equals 20 hours a second failure after 140 hours

solution

We are aware that the formula for the mean time between failures is: = (total uptime) / (number of breakdowns)...................1.

hence, the Total Uptime here will be

Uptime total = 200 x 10

2000 hours total uptime

and this

1 at 20 hours and another at 140 hours equals the number of breakdowns.

Therefore, the equation will be: = (Total up time) (Number of breakdowns)...2

= = 1000

there is a gap between these instances.

occurrences separated by 140 - 20

gap = 120 hours between occurrences

and

MTBF is going to

MTBF = 1000 - 120

MTBF equals 880 hrs.

and

There will be a failure rate (FR).

Failure rate (FR) = 1 Mean Time Between Failures................3

Reject rate=20%

To know more about failure rate visit:-

https://brainly.com/question/13652179

#SPJ4

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.