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Sagot :
The orbital period of Hyperion is approximately 23.55 days. The orbital period of a celestial object is the time it takes for the object to complete one orbit around another object.
To predict the orbital period of Hyperion, we can use the formula for Kepler's Third Law of Planetary Motion, which states that the square of the orbital period of a celestial body is directly proportional to the cube of the semimajor axis of its elliptical orbit.
In this case, the semimajor axis of Titan's orbit is 1.22x10^9 m and the semimajor axis of Hyperion's orbit is 1.48x10^9 m. We can use these values to calculate the ratio of the two orbital periods:
(orbital period of Hyperion / orbital period of Titan)² = (semimajor axis of Hyperion / semimajor axis of Titan)³
Solving for the orbital period of Hyperion, we get:
orbital period of Hyperion = √((semimajor axis of Hyperion / semimajor axis of Titan)³) x orbital period of Titan
Plugging in the values, we get:
orbital period of Hyperion = sqrt((1.48x10^9 m / 1.22x10^9 m)^3) * 15.95 days
= √(1.21³) x 15.95 days
= 1.49 x 15.95 days
= 23.55 days
Therefore, the orbital period of Hyperion is approximately 23.55 days.
Learn more about orbital period, here https://brainly.com/question/14494804
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