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How do I graph x-y=8 and x+y=-2

Sagot :

put the equation into slope-intercept form: y=mx+b
I'll do the first one and you try the second. 
   x-y=8     To move the x from the other side simply subtract it from both sides.
  -y=8-x     divide by negative 1 (because -y has a coefficient of -1)
  y=-8+x    rearrange...
 y=x-8

You'll notice that the "m" from the top equation isn't shown. this means that it is 1 because x actually has a coefficient of 1 in front of it. This can be written as 1/1.

To graph start at (-8,0) and (because the m or slope is 1/1) Go up 1 and over 1 to the right then connect the dots to graph the line.

Hope that helps. Good luck!!
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