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Sagot :
The slopes of the equations are 3/2, -3, -3/2, and -2/3
For any straight line, the standard equation is
y = mx + c
where m is the slope of the line.
Hence to find the slope of a line from its equation we need to bring it down to the form and check the coefficient of x.
The first equation is -3x + 2y −4 = 0
or, 2y = 3x + 4
or, y = 3/2x + 2
Hence the slope is 3/2.
The next equation is
2y + 6x = 4
or, 2y = 4 - 6x
or, y = -3x + 2
Therefore, the slope is -3.
The next equation is 2y = -3x + 1
or, y = -3/2x + 1/2
Hence the slope is -3/2
The last equation is 2x + 3y = -12
or, 3y = -2x -12
or, y = -2/3x -4
Hence the slope is -2/3
To know more about straight lines visit
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Complete Question
What is the slope of the linear equation below -3x + 2y −4 = 0?; What is the slope of 2y + 6x = 4?; What is the slope of 2y = -3x + 1?; What is the slope of the line represented by the equation 2x + 3y = -12?
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