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Sagot :
The equation of the line that passes through points P(-5,3) and with slope 3/5 is: 3x - 5y + 30 = 0
Equation of straight line passing through the point Q(5,8) with slope equal to 3/5: 3x - 5y + 25 = 0;
Equation of straight line passing through the point R(5,4) with slope = 2: 2x - y = 6;
The equation of straight line passing through the point S(6,3) and T(14,-5): cannot be defined as the slope consists of 0 in its denominator.
The equation of the line that passes through points P(-5,3) and with slope 3/5 is:
Formula: y-y₁=m(x-x₁)
y-3=3/5(x-(-5))
5(y-3)=3(x+5)
5y -15 = 3x +15
3x - 5y =-15 - 15
3x - 5y = -30
3x - 5y + 30 = 0
Equation of straight line passing through the point Q(5,8) with slope equal to 3/5
y-8 = 3/5 (x-5)
5(y-8) = 3(x-5)
5y - 40 = 3x - 15
3x - 5y - 15 + 40 = 0
3x - 5y + 25 = 0;
Equation of straight line passing through the point R(5,4) with slope = 2
y - 4 = 2( x - 5)
y - 4= 2x - 10
2x -y = 10 - 4
2x - y = 6;
The equation of straight line passing through the point S(6,3) and T(14,-5) is:
Formula: y-y₁ =y₂-y₁/x₂-x₁ (x-x₁)
y-(-5) = [3-(-5)]/[6-14] (x-14)
y + 5 = 3+8/-8 (x-14)
y + 5 = 11/-8 (x-14)
-8(y+5)= 11(x-14)
-8y - 40 = 11x - 154
11x + 8y = 154 - 40
11x + 8y = 114
The equation of a line passing through point L(5,7) and M(5,-2)
y-(-2) = 7-(-2)/5-5(x-5)
y+2 = 9/0(x-5)
as 9/0 is undefined, we cannot write the equation of line for these two points.
Learn more about straight line at:
brainly.com/question/28951560
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