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what is the equation of the line that passes through the point (-5 3 and has a slope of 3,5); what is the equation of the line that passes through the point (5 8 and has a slope of 3/5); slope 4 3 passes through (-5,6); what is the equation of the line that passes through the point (3,5) and has a slope of 2?; what is the equation of the line that passes through the point (5,4) and has a slope of 2?; desmos; passes through (6,3) and (14,-5); write an equation of the line passing through the point (5,7) and (5, -2).

Sagot :

The equation of the line that passes through points P(-5,3) and with slope 3/5 is: 3x - 5y + 30 = 0

Equation of straight line passing through the point Q(5,8) with slope equal to 3/5: 3x - 5y + 25 = 0;

Equation of straight line passing through the point R(5,4) with slope = 2: 2x - y = 6;

The equation of straight line passing through the point S(6,3) and T(14,-5): cannot be defined as the slope consists of 0 in its denominator.

The equation of the line that passes through points P(-5,3) and with slope 3/5 is:

Formula: y-y₁=m(x-x₁)

y-3=3/5(x-(-5))

5(y-3)=3(x+5)

5y -15 = 3x +15

3x - 5y =-15 - 15

3x - 5y = -30

3x - 5y + 30 = 0

Equation of straight line passing through the point Q(5,8) with slope equal to 3/5

y-8 = 3/5 (x-5)

5(y-8) = 3(x-5)

5y - 40 = 3x - 15

3x - 5y - 15 + 40 = 0

3x - 5y + 25 = 0;

Equation of straight line passing through the point R(5,4) with slope = 2

y - 4 = 2( x - 5)

y - 4= 2x - 10

2x -y = 10 - 4

2x - y = 6;

The equation of straight line passing through the point S(6,3) and T(14,-5) is:

Formula: y-y₁ =y₂-y₁/x₂-x₁ (x-x₁)

y-(-5) = [3-(-5)]/[6-14] (x-14)

y + 5 = 3+8/-8 (x-14)

y + 5 = 11/-8 (x-14)

-8(y+5)= 11(x-14)

-8y - 40 = 11x - 154

11x + 8y = 154 - 40

11x + 8y = 114

The equation of a line passing through point L(5,7) and M(5,-2)

y-(-2) = 7-(-2)/5-5(x-5)

y+2 = 9/0(x-5)

as 9/0 is undefined, we cannot write the equation of line for these two points.

Learn more about straight line at:

brainly.com/question/28951560

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