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solve the system of linear equations by elimination. −x+y=4 x+3y=4; solve the system of linear equations by elimination. 5x+6y=50 x−6y=−26; solving by elimination; systems of equations; systems of linear equations

Sagot :

The value of x and y for the first set of equations is -2 and 2 respectively, while the value of x and y for the next set of equations is 4 and 5 respectively.

We have equations

-x + y = 4                               [1]

x + 3y = 4                             [2]

Here we see that we can eliminate x by simply adding [1] and [2] up
we get

4y = 8

or, y = 2

Putting this equation [1] we get

-x + 2 = 4

or, -x = 2

or, x = -2

The next set of equations is

5x+6y=50                             [3]

x−6y=−26                             [4]

here we can eliminate y. hence we get

6x = 24

or, x = 4

putting this value in equation [3] we get

4 - 6y = -26

or, 6y = 4 + 26

or, y = 30/6

or, y = 5

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