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A box of chocolates contains 2 1/3 ounces of fruit

Sagot :

The equation that can be used to solve the problem is 2 [tex] \frac{1}{3} [/tex] + c = 8 [tex] \frac{5}{6} [/tex].

Let us represent the quantity of caramel by c.

So, the sum of weights of chocolates and caramel makes up the weight of box. Hence, it will be represented as -

2 [tex] \frac{1}{3} [/tex] + c = 8 [tex] \frac{5}{6} [/tex]

Now, we will convert mixed fraction to fractions for ease of calculation.

Weight of chocolates = 2 [tex] \frac{1}{3} [/tex]

Weight of chocolates = (3×2)+1/3

Weight of chocolates = 7/3 ounces

Total weight of box = 8 [tex] \frac{5}{6} [/tex]

Total weight of box = (8×6)+5/6

Total weight of box = 53/6 ounces

Rewriting the equation now -

7/3 + c = 53/6

c = 53/6 - 7/3

Taking LCM

c = 53 - (7×2)/6

Performing multiplication on Right Hand Side of the equation

c = 53 - 14/6

Performing subtraction

c = 39/6

Converting back to mixed fraction -

c = 6 [tex] \frac{3}{6} [/tex]

Thus, the caramel weight is 6 [tex] \frac{3}{6} [/tex] ounces.

Learn more about fractions -

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