Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A box of chocolates contains 2 1/3 ounces of fruit

Sagot :

The equation that can be used to solve the problem is 2 [tex] \frac{1}{3} [/tex] + c = 8 [tex] \frac{5}{6} [/tex].

Let us represent the quantity of caramel by c.

So, the sum of weights of chocolates and caramel makes up the weight of box. Hence, it will be represented as -

2 [tex] \frac{1}{3} [/tex] + c = 8 [tex] \frac{5}{6} [/tex]

Now, we will convert mixed fraction to fractions for ease of calculation.

Weight of chocolates = 2 [tex] \frac{1}{3} [/tex]

Weight of chocolates = (3×2)+1/3

Weight of chocolates = 7/3 ounces

Total weight of box = 8 [tex] \frac{5}{6} [/tex]

Total weight of box = (8×6)+5/6

Total weight of box = 53/6 ounces

Rewriting the equation now -

7/3 + c = 53/6

c = 53/6 - 7/3

Taking LCM

c = 53 - (7×2)/6

Performing multiplication on Right Hand Side of the equation

c = 53 - 14/6

Performing subtraction

c = 39/6

Converting back to mixed fraction -

c = 6 [tex] \frac{3}{6} [/tex]

Thus, the caramel weight is 6 [tex] \frac{3}{6} [/tex] ounces.

Learn more about fractions -

https://brainly.com/question/78672

#SPJ4

The complete question is attached in figure.

View image QWTiffany
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.