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A bag of jelly beans contains 10 red 6 green 7 yellow and 5 orange jelly beans. What is the probability of randomly choosing a red jellybean, and then choosing another jellybean, replacing it,and then randomly choosing an orange jellybean?

Sagot :

ayune

A bag of jelly beans contains 10 red 6 green 7 yellow and 5 orange jelly beans. The probability of randomly choosing a red jellybean followed by an orange one, if the pickup jelly is replaced, is 25/392.

Probability of an event is defined as:

Probability(event A) = number of ways the event A can happened / total possible outcomes.

Suppose an event A and B are independent, then
P(A and B) = P(A) x P(B)

In the given problem, since the jelly is replaced after being picked up, then the occurrences that the chosen jelly is a red one and a orange one are independent events.

Total jelly = 10 + 6 + 7 + 5 = 28

P(red) = 10 / 28

P(orange) = 5/28

P(red, orange) = 10/28 x 5/28 = 50/784 = 25/392.

Learn more bout probability here:

https://brainly.com/question/28712149

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