AERONAUTICS At liftoff, the space

shuttle Discovery has a constant

acceleration of 16.4 feet per second

squared and an initial velocity of

1341 feet per second due to the rotation

of Earth. The distance Discovery has

traveled t seconds after liftoff is given by

the equation d(t) = 1341t + 8.2t^2 How

long after liftoff has Discovery traveled

40,000 feet? Round your answer to the

nearest tenth.

Question

salamahmohammedsaeed salamahmohammedsaeed

07-12-2022
Mathematics

Answered

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AERONAUTICS At liftoff, the space

shuttle Discovery has a constant

acceleration of 16.4 feet per second

squared and an initial velocity of

1341 feet per second due to the rotation

of Earth. The distance Discovery has

traveled t seconds after liftoff is given by

the equation d(t) = 1341t + 8.2t^2 How

long after liftoff has Discovery traveled

40,000 feet? Round your answer to the

nearest tenth.

Sagot :

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