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Sagot :

The equation of the line is perpendicular to the line y = -4x  - 3 and passes through the point (10, 6) is y = 1 / 4 x + 7 / 2.

How to find the equation of a line?

The equation of a line can be represented in slope intercept form as follows:

y = mx + b

where

  • m = slope
  • b = y-intercept

Therefore, the equation of the line is perpendicular to the line y = -4x  - 3 and passes through the point (10, 6).

Perpendicular lines follows the rule:

m₁ m₂ = -1

-4m₂ = -1

m₂ = 1 / 4

Let's find the y-intercept of the equation using (10, 6)

y = 1 / 4 x + b

6 = 1 / 4 (10) + b

6 = 5 / 2 + b

b = 6 - 5 / 2

b =  12 - 5/ 2

b = 7 / 2

Therefore, the equation of the line is y = 1 / 4 x + 7 / 2

learn more on equation of a line here: https://brainly.com/question/21511618

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