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Sagot :
The equation of the line that passes through the points (-3,-1) and (6,2) is x - 3y = 0 OR x = 3y
Determining the equation of a line
From the question, we are to determine the equation of the line that passes through the given points
The given points are (-3, -1) and (6, 2)
Using the formula,
(y - y₁) / (x - x₁) = (y₂ - y₁) / (x₂ - x₁)
Then,
(y - (-1)) / (x - (-3)) = (2 - (-1)) / (6 - (-3))
Simplify
(y + 1) / (x + 3) = (2 + 1) / (6 + 3)
(y + 1) / (x + 3) = 3/9
(y + 1) / (x + 3) = 1/3
Cross multiply
3(y + 1) = 1(x + 3)
3y + 3 = x + 3
Thus,
x + 3 = 3y + 3
x - 3y = 3 - 3
x - 3y = 0
Hence, the equation is x - 3y = 0
Learn more on Equation of a line here: https://brainly.com/question/21967006
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