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Which shows the image of quadrilateral ABCD after the transformation R0, 90°?
B
What is the final transformation in the composition of transformations that maps pre-image ABCD to image A"B'C"D"?
a 270° rotation about point B'

Sagot :

main answer:As we know, when a figure is rotated 90° counterclockwise about the origin, the sides of the figure's points are switched and the sign of the y-coordinate is reversed.

supporting answer

The movement of geometric figures is called transformation. There are different types of transformations called translation, rotation and reflection.

body of the answer:Consider the quadrilateral ABCD in the first figure, which has vertices A(-1, 0), B(0, -1), C(-2, -3) and D(-3, -2).

So, after rotating quadrilateral ABCD 90° counterclockwise around the origin,

A (-1, 0) (-1, 0)

A' → (-y,x) = (0,1) (0,1)

B(0, -1)

B' → (-y,x) = (1, 0)

C(-2, -3)

C' → (-y,x) = (3, -2)

D(-3, -2) (-3, -2)

D' → (-y,x) = (2, -3) (2, -3)

After a 90° rotation about the origin, the coordinates of a quadrilateral ABCD would be A'(0, 1), B'(1, 0), C'(3, -2), and D'(2, -3), respectively.

(b)

Point B' and the centre of rotation are shared by the last two figures. Each segment of the figure A"B'C"D" is rotated 90 degrees clockwise from the corresponding segment of A'B'C'D'. A 90-degree clockwise rotation is equivalent to a 270-degree counterclockwise rotation.

final answer:As a result, its coordinates are A'(0, 1), B'(1, 0), C'(3, -2), and D'(3, -2). (2, -3).

to learn more about quadrilateral transformation from the given work

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