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Sagot :
Equation employing the slope-intercept method for two points
The slope-intercept version of the equation may be used to calculate the two-point Y-intercept.
The shape of a point-slope is[tex]\mathbf{Y-Y_{1} = m(X-X_{1})}.[/tex]
Steps to find the y-intercept with two ordered pairs?
Determine the slope using two points.
[tex]Slope = \frac{Y_{2}-Y_{1}}{X_{2}-X_{1}} = \frac{Rise}{Run} = \frac{\bigtriangleup Y}{\bigtriangleup X}[/tex]
As an illustration, two points are (3, 5) and (6, 11)
Slope = [tex]\frac{Y_{2}-Y_{1}}{X_{2}-X_{1}} = \frac{11 - 5}{6 - 3} = \frac{6}{3} = 2[/tex]
In the slope-intercept form of the equation, substitute the slope(m).
[tex]\\y = mx+b \\y = 2x+b[/tex]
Either point may be substituted in the equation. You may either use (3,5) or (6,11).
[tex]\\y = 2x+b \\5 = 2(3)+b[/tex]
Find the answer to the equation for b, the line's y-intercept.
[tex]\\5 \ \ \ = 2(3) + b \\5 \ \ \ = 6 + b \\\underline{-6\ = -6 \ \ \ \ \ \ \ } \\-1 = b[/tex]
Substitute b, into the equation.
[tex]\\y = 2x + b \\y = 2x - 1[/tex]
Learn more about y-intercept with two ordered pairs from the link below
https://brainly.com/question/10708360
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