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How many grams of oxygen are required to burn completely 570g of octane?

Sagot :

With 8 carbon atoms, octane is a hydrocarbon. Oxygen and 2 moles of octane react. Therefore, 62.5 mol of oxygen was produced when 5 moles of octane reacted with 252 moles of octane. The needed mass of oxygen is 19.5 moles times a mass per mole of 312 g.

To completely burn 3 moles of butane gas, 312 grams of oxygen are therefore essentially needed. Thus, eight moles of CO2 with a weight of 352 grams would be produced by burning one mole of octane (114 grams) (8 x 44). As a result, 352/114, or around 3 to 1, is the weight ratio of CO2 created per octane molecule consumed. 110 makes up 3/5 of the total, or 0.60 (or 60%), of the mixture. 2/5 = 0.40 (40%), which is the mixture's percentage of 100 octane fuel.

To know more about octane molecules,

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