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Sagot :
When x^3+3x^2+3x+1 is divided by (x+1) then remainder is 0.
In the given question, we have to find what is remainder when x^3+3x^2+3x+1 is divided by (x+1).
To find the remainder there are two ways. First we divide the x^3+3x^2+3x+1 by (x+1). Second we find the value of from (x+1) by equating (x+1) equal to zero. The put the value of x in the expression x^3+3x^2+3x+1.
In this we ca easily find the remainder.
Now we firstly find the value of x;
(x+1) = 0
Subtract 1 on both side we get;
x= −1
Now put x=-1 in the expression x^3+3x^2+3x+1.
x^3+3x^2+3x+1 = (−1)^3+3(−1)^2+3(−1)+1
x^3+3x^2+3x+1 = −1+3−3+1
x^3+3x^2+3x+1 = 0
Hence, when x^3+3x^2+3x+1 is divided by (x+1) then remainder is 0.
To learn more about division of polynomial link is here
brainly.com/question/29631184
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The right question is:
What is remainder when x^3+3x^2+3x+1 is divided by (x+1)?
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