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Sagot :
When x^3−2x^2 +x+1 is divided by (x−1) then remainder is 2.
In the given question, we have to find what is remainder when x^3−2x^2 +x+1 is divided by (x−1).
To find the remainder there are two ways. First we divide the x^3−2x^2 +x+1 by (x−1). Second we find the value of from (x−1) by equating (x−1) equal to zero. The put the value of x in the expression x^3−2x^2 +x+1.
In this we ca easily find the remainder.
Now we firstly find the value of x;
(x−1) = 0
Add 1 on both side we get;
x=1
Now put x=1 in the expression x^3−2x^2 +x+1.
x^3−2x^2 +x+1 = (1)^3−2(1)^2+1+1
x^3−2x^2 +x+1 = 1−2+1+1
x^3−2x^2 +x+1 = 2
Hence, when x^3−2x^2 +x+1 is divided by (x−1) then remainder is 2.
To learn more about division of polynomial link is here
brainly.com/question/29631184
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The right question is:
What is remainder when x^3−2x^2 +x+1 is divided by (x−1)?
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