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Sagot :
When x^3-3x^2+5x-7 is divided by (x-2) then remainder is -1.
In the given question, we have to find what is remainder when x^3-3x^2+5x-7 is divided by (x-2).
To find the remainder there are two ways. First we divide the x^3-3x^2+5x-7 by (x-2). Second we find the value of from (x-2) by equating (x-2) equal to zero. The put the value of x in the expression x^3-3x^2+5x-7.
In this we ca easily find the remainder.
Now we firstly find the value of x;
(x-2) = 0
Add 2 on both side we get;
x= 2
Now put x=2 in the expression x^3-3x^2+5x-7.
x^3-3x^2+5x-7 = (2)^3-3(2)^2+5(2)-7
x^3-3x^2+5x-7 = 8-12+10-7
x^3-3x^2+5x-7 = -1
Hence, when x^3-3x^2+5x-7 is divided by (x-2) then remainder is -1.
To learn more about division of polynomial link is here
brainly.com/question/17167810
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The right question is:
When x^3-3x^2+5x-7 is divided by (x-2) then the remainder is?
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