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Sagot :
Equation 4x - y = 13 represents the line that passes through the point (3,-1) and is perpendicular to the graph of x+4y=13
According to the question,
Its given that
The required line is passing through (3, -1)
And is perpendicular to line x + 4y = 13
Let required line be (y-y') = m'(x - x') ----(1)
Where m' is slope of required line
The given line is x + 4y = 13
Slope of this line be m =>
=> 4y = 13 - x
=> y = 13/4 - x/4
m = -1/4
You should know that if two lines are perpendicular to each other than the product of their slope is always -1
Therefore , m × m' = -1
=> -1/4 × m' = -1
Multiplying by -4
=> m' = 4
Substituting the value in equation (1)
=> (y - (-1)) = 4 ( x - 3)
=> y + 1 = 4x - 12
=> 4x - y = 13 is our required equation
To know more about Equation of line here
https://brainly.com/question/2564656
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