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Sagot :
0.8 M is the molarity of 40g of NaOH dissolved in 1.25 Litre of water
To find the molarity of solution we will use following expression ;
Molarity (M) = n/V(ml)×1000
Where, n = number of moles of solute
V = volume of solution in ml.
In the given problem,
NaOH is Solute in solution
Given mass of sodium hydroxide = 40 grams
Molar mass of NaOH = 40 g/mol
Total volume of the solution = 1.25 L
Number of moles of sodium hydroxide(n):-
n = mass of NaOH/molar mass of NaOH
n = 40g/(40g/mo)l
n = 1 mole of NaOH
Substitute the values of volume and number of moles of solution in the molarity formula,
Molarity (M) = 1mole/1.25 L
M = 0.8 M
Hence, The Molarity of NaOH is 0.8 M.
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