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Sagot :
Triangle ABC to be isosceles we need to prove that opposite pair of sides of triangle ABC are congruent to each other.
Explanation :
Let us consider a triangle ABC,
To prove : Triangle ABC is an isosceles triangle.
- In triangle ABC draw perpendicular bisector through point A to BC at point D.
In triangle ADC and triangle ADB,
m ∠CAD ≅ m ∠BAD ( AD bisect angle A )
AD = DA ( common side )
m ∠ADC ≅ m ∠ADB ( each 90° )
By Angle side angle (ASA ) theorem ,
ΔADC ≅ΔADB
By congruence parts congruent triangles :
AC ≅ AB
Therefore, by congruence parts congruent triangles side AC ≅ AB implies ABC is an isosceles triangle.
Learn more about triangles here
brainly.com/question/2773823
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