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Sagot :
The spring constant is 50000 N/m.
The spring constant is a measure of the stiffness of a spring.
- Springs with higher stiffness are more difficult to stretch.
- Under the action of external forces, the spring is deformed and returns to its original position when the force is removed.
- Spring constant is denoted by 'k' and has a SI unit as N/m.
- It has different values for different springs and different material.
Electric potential energy of a spring can be calculated as P.E. = (1/2)*k*x²
where, k is the spring constant,
x is the displacement caused by the spring
The spring stores energy = 100 J
Displacement suffered by the spring = 2 cm = 0.02 m
P.E. = (1/2)*k*x²
k = (2*P.E.) / x²
k = (2 * 100) / (0.02)²
k = 200 / 0.0004
k = 50000 N/m
The spring constant for a spring having potential energy as 100 J is 50000 N/m.
The question is incomplete the complete question is "When a spring is stretched by 2 cm its potential energy is 100J? What is the spring constant".
To know more about spring constant,
https://brainly.com/question/11550087
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