Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. The equation of a line that is perpendicular to Y = -3x^2 is: X = -3y^2/2
The equation of a line that is perpendicular to a given line is found by changing the sign of the slope of the given line and taking the reciprocal of the slope.
The slope of the given line Y = -3x^2 is -3, so the slope of the line perpendicular to it is 3.
The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
Therefore, the equation of a line that is perpendicular to Y = -3x^2 is: x = 3y + b
We can now solve for the y-intercept, b, by substituting the point (0,0) into the equation:
x = 3y + b
0 = 3(0) + b
b = 0
Therefore, the equation of a line that is perpendicular to Y = -3x^2 is: x = 3y^2/2
Learn more about slope here
https://brainly.com/question/3605446
#SPJ4
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.