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Sagot :
The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. The equation of a line that is perpendicular to Y = -3x^2 is: X = -3y^2/2
The equation of a line that is perpendicular to a given line is found by changing the sign of the slope of the given line and taking the reciprocal of the slope.
The slope of the given line Y = -3x^2 is -3, so the slope of the line perpendicular to it is 3.
The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
Therefore, the equation of a line that is perpendicular to Y = -3x^2 is: x = 3y + b
We can now solve for the y-intercept, b, by substituting the point (0,0) into the equation:
x = 3y + b
0 = 3(0) + b
b = 0
Therefore, the equation of a line that is perpendicular to Y = -3x^2 is: x = 3y^2/2
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