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What is the equation of a line that is perpendicular to Y =- 3x 2?

Sagot :

The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. The equation of a line that is perpendicular to Y = -3x^2 is: X = -3y^2/2

The equation of a line that is perpendicular to a given line is found by changing the sign of the slope of the given line and taking the reciprocal of the slope.

The slope of the given line Y = -3x^2 is -3, so the slope of the line perpendicular to it is 3.

The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

Therefore, the equation of a line that is perpendicular to Y = -3x^2 is: x = 3y + b

We can now solve for the y-intercept, b, by substituting the point (0,0) into the equation:

x = 3y + b

0 = 3(0) + b

b = 0

Therefore, the equation of a line that is perpendicular to Y = -3x^2 is: x = 3y^2/2

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