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Sagot :
The equation of the line is [tex]2x+y=1[/tex] passing through the points [tex](-1,3)[/tex] and [tex](2,3)[/tex]
The general equation can be written as [tex]y=mx+c[/tex]
where m is the slope and c is the intercept
The equation of a line passing through the points [tex](x_{1,} y_{1})[/tex] and [tex](x_{2,} y_{2})[/tex]
slope [tex]m=\frac{y_{2}-y_{1} }{x_{2} -x_{1} }[/tex]
The equation is [tex]y-y_{1} =m(x-x_{1} )..........(1)[/tex]
[tex]m=\frac{y_{2}-y_{1} }{x_{2} -x_{1} }\\m=\frac{-3-3}{2-(-1)} \\m=\frac{-6}{3} \\m=-2[/tex]
Put this value in 1 equation
[tex]y-3=-2(x+1)\\y-3=-2x-2\\y=-2x+1\\2x+y=1[/tex]
Learn more about equation from
https://brainly.com/question/9585437
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