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Sagot :
The equation of the straight line passing through the point (1/2, 0) and parallel to the line y = 3x + 1 is y = 3x - ½ with slope m1 = 3 and m2 = 3.
Given line is y = 3x + 1
We need to find equation of line parallel to this line
Let us consider the equation of line as y = mx + c
We know that two lines are parallel if they have same slope i.e. m1 = m2
Here m1 = 3
So slope of required line m2 = 3
We need to find the value of c
Let us take a point (x1, y1) common to both lines
We know that (1/2, 0) is common to both lines
So x1 = 1/2, y1 = 0
Substituting these values in y = mx + c
0 = 3(1/2) + c
=> c = -1/2
Hence the equation of straight line passing through the point (1/2, 0) and parallel to the line y = 3x + 1 is y = 3x - 1/2.
Learn more about slope here
https://brainly.com/question/3605446
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