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Sagot :
The equation of a line that passes through (1/3, 2) is y = 6x – 4 with slope.
1. To solve for the equation of the line, we need to use the point-slope form.
2. The point-slope form is y-y1=m(x-x1).
3. We are given the point (1/3, 2). We can plug this into the equation as x1=1/3 and y1=2.
4. To find the slope (m), we need to calculate the rise over run. We can use the point (1/3, 2) and another point to calculate the slope.
5. Let's choose the point (0,0). The rise is 2 and the run is 1/3. So the slope (m) is 6.
6. Now we can plug our values into the point-slope form and solve for y.
7. y-2=6(x-1/3).
8. We can simplify this equation by subtracting 2 from both sides.
9. y=6x-4.
10. This is the equation of the line that passes through (1/3, 2).
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