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Sagot :
y = 3x – 2 is the equation of the line which passes through 1/3 and 2 5 with slope.
We can use the slope-intercept form of the equation of a line, which is y = mx + b, where m is the slope and b is the y-intercept. We know one point on the line, which is (1/3, 2.5). We can calculate the slope by calculating the rise (change in y) divided by the run (change in x), which is (2.5 - 0) / (1/3 - 0) = 2.5 / 0.33 = 7.5. Therefore, the equation of the line is y = 7.5x + b. To solve for b, we can substitute in our point, (1/3, 2.5) into the equation. We get 2.5 = 7.5(1/3) + b, or 2.5 = 2.5 + b. Therefore, b = 0, and the equation of the line is y = 7.5x + 0, or y = 7.5x.
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