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Sagot :
The equation of the line that passes through the points (2, 1 ) and (4,5) in the Cartesian coordinate plane is y = (2/3)(x - 4) + 5.
By subtracting the y coordinates [5 - 1] = 4, we get
Subtract the x coordinates in the same order [4 - (-2)] = [4 + 2] = 6
The slope is given by y-coordinate/x-coordinate = 4/6 = 2/3.
Now, just choose one point say (4,5), and substitute the coordinates in this formula-
y - [y-coordinate of our point] - (slope)* [ x - ( the x-coordinate of our point)]
y - 5 = (2/3)(x - 4) ...........(adding 5 to both sides)
y = (2/3)(x - 4) + 5
Hence, the equation of the line in the "slope-intercept" form is y = (2/3)(x - 4) + 5.
Read more about the Equation of a line:
brainly.com/question/24907633
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The complete question is -
what is the equation of the line that passes through the points (-2,1) and (4,5) in the cartesian coordinate plane?
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