The equation of the line through (1, 2) so that the segment of the line intercepted between the axes is y+2x=4.
Let's use the slope-intercept form to find the equation of the line,
Hence the equation of the line would be of the form y=mx+c,
now the point at which the line intersects X-axis is (a,0), and the point at which it intersects Y-axis is (0,b).
⇒ m×a+c = 0
⇒a= − c/m
and b=c+0 ⇒ b=c
Now, (1,2) is the midpoint of (a,0) and (0,b)
ie. 2=(0+b)/2 ⇒ c/2 =2
⇒c = 4
and 1=(a+0)/2 ⇒ 1= −c/2m
⇒ m= −c/2
⇒ m= −2
∴ The equation of the line is given by y+2x=4.
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The complete question is-
What is the equation of the line through (1, 2) so that the segment of the line intercepted between the axes is?