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The velocity of a parachutist as a function of time is given by [tex]v=v_f + (v_0+v_f)e^(^-^t^/^2^.^5^)[/tex], where[tex]t=0s[/tex] corresponds to the instant the parachute is opened, [tex]v_0=180 km/h[/tex] is the velocity before opening of the parachute, and [tex]v_f=22km/h[/tex] is the final (terminal) velocity.
What acceleration does the parachutist experience just after opening the parachute?

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