At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Write the electron configuration for a neutral atom of selenium!

Sagot :

The electronic configuration of neutral atom of selenium is

           1s2 2s2 2p6 3s2 3p6 3d10 4s2  4p4.

Chemical element selenium has the symbol Se and its atomic number is 34. It comes in the category of non-metals. Selenium consists of 34 electrons distribution in its 4 orbits. Valence electrons are the electrons which are located in the outermost shell of the atom or molecule. Selenium has 6 electrons in its outermost shell

So electronic configuration of selenium define as:

     1s2 2s2 2p6 3s2 3p6 3d10 4s2  4p4.

The neutral atom in selenium is Ar. so, The electronic configuration of Argon  is represented as ,

        1s2 2s2 2p6 3s2 3p6

The number of valence electrons is defined as the number of electrons present in the outermost shell of the atom. So, in the case of selenium, there are 6 valence electrons. so, like this we can write the electronic configuration of selenium.

To learn more about Electronic configuration please visit:

https://brainly.com/question/26084288

#SPJ4

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.