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A 2. 0 kg body is initially traveling at a velocity of 40 m/s east. If a constant force of 10 n due east is applied to the body for 5. 0 s, the final speed of the body is.

Sagot :

The Final speed of the body is = 65 m/s

The values that are given in the question are,

Mass of body = 2.0 kg

Velocity of the body = 40 m/s

Force = 10 N

Time = 5.0 s

Firstly we need to calculate the momentum change of the body,

The formula for change in momentum,

⇒ Change in momentum = Force x Time

⇒ Change in momentum = 10 x 5.0

⇒ Change in momentum = 50 kg-m/s

Now we have to calculate the change in velocity,

⇒ Change in velocity = Change in momentum / Mass

⇒ Change in velocity = 50 / 2.0

⇒ Change in velocity = 25 m/s towards east

Now to calculate the final velocity

⇒ Final velocity = initial velocity + change in velocity

⇒ Final Velocity = 40 + 25 = 65 m/s

Therefore, the final speed of the body is = 65 m/s

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