Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
An earthquake's energy output when it has a magnitude of 2.7 is 4.5 × [tex]10^{12}[/tex].
The magnitude of an earthquake is the most common indicator of its size. It serves as a barometer for the size of an earthquake's single source. Because it is the same no matter where and how you see it, the following calculation may be done:
magnitude, M = 2 ÷ 3 log(E ÷ [tex]E_{0}[/tex])
Where E is the power generated in Joules and M is the lowest magnitude emitted by such an earthquake, [tex]E_{0} = 10^{4.4}[/tex].
Assuming 5.5, the same magnitude is provided when the preceding equation is used:
M = 2 ÷ 3 log(E ÷ [tex]E_{0}[/tex])
5.5 = 2 ÷ 3 log(E ÷ [tex]E_{0}[/tex])
8.25 = [tex]log(\frac{E}{10^{4.4}})[/tex]
[tex]10^{8.25}[/tex] = [tex]\frac{E}{10^{4.4}}[/tex]
E = [tex]10^{4.4}[/tex] × [tex]10^{8.25}[/tex]
E = 4.5 × [tex]10^{12}[/tex]
Therefore the final answer is 4.5 × [tex]10^{12}[/tex].
Learn more about the energy at
https://brainly.com/question/10439300?referrer=searchResults
#SPJ4
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
