Answered

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Write an equation of the line passing through point $p\left(4,-6\right)$ that is perpendicular to the line $y=-3$.

Sagot :

The equation of the line passing through point P(4,-6) and perpendicular to the line y = -3 is x = 4.

A number that identifies the direction and steepness of a line is its slope or gradient. The slope of the straight line is written as y=mx+c where m is the slope and c is the y-intercept.

Given the equation of a line is y = -3 and point P(4,-6).

From the given equation, we can say that y is a horizontal line. The line perpendicular to this horizontal line will be a vertical line. The equation of the line perpendicular to y is of the form x = n where n is the x-coordinate of the point passing through this line.

Here, the x-coordinate is 4 from the point (4,-6). Then, the required line is x=4.

To know more about the slope:

https://brainly.com/question/16941905

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