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Sagot :
If you mated a heterozygous male with a heterozygous female The phenotypes of the offspring would be 25% black feathers, 50% gray feathers, and 25% white feathers.
If we cross Bb with Bb (heterozygous male with a heterozygous female)
B b
B BB Bb
b Bb bb
We are aware that both males and females are heterozygous, which means that their alleles differ, so one would be dominant and the other would be recessive. Thus, Bb would be the same for both men and women, as in the punnet square. We get BB, Bb, Bb, and bb if we cross them. Therefore, black feathers, or BB, account for 25% of that. We have 25% white feathers (bb) and 50% gray feathers (Bb). Therefore,
know more about punett's square here: https://brainly.com/question/15956858
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